So I've got to find the general solution of the following, and this is my work... did I do it right?

$\displaystyle (1+x)\frac{dy}{dx}=4y$

$\displaystyle (4+4x)\frac{dy}{dx}=y$

$\displaystyle \frac{dy}{y}=\frac{dx}{4+4x}$

$\displaystyle ln|y|=\frac{1}{4}ln|4x+4|$

$\displaystyle y=\frac{+}{-}x+1$