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Math Help - Is my work right?

  1. #1
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    Is my work right?

    So I've got to find the general solution of the following, and this is my work... did I do it right?

    (1+x)\frac{dy}{dx}=4y
    (4+4x)\frac{dy}{dx}=y
    \frac{dy}{y}=\frac{dx}{4+4x}
    ln|y|=\frac{1}{4}ln|4x+4|
    y=\frac{+}{-}x+1
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  2. #2
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    Quote Originally Posted by Rhode963 View Post
    So I've got to find the general solution of the following, and this is my work... did I do it right?

    (1+x)\frac{dy}{dx}=4y

    (4+4x)\frac{dy}{dx}=y Mr F says: This is wrong. You should be dividing by 4. This mistake has consequences.

    \frac{dy}{y}=\frac{dx}{4+4x}
    ln|y|=\frac{1}{4}ln|4x+4|
    y=\frac{+}{-}x+1
    ..
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  3. #3
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    Don't forget the integrating constant.
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