# Is my work right?

• September 30th 2010, 04:28 PM
Rhode963
Is my work right?
So I've got to find the general solution of the following, and this is my work... did I do it right?

$(1+x)\frac{dy}{dx}=4y$
$(4+4x)\frac{dy}{dx}=y$
$\frac{dy}{y}=\frac{dx}{4+4x}$
$ln|y|=\frac{1}{4}ln|4x+4|$
$y=\frac{+}{-}x+1$
• September 30th 2010, 09:27 PM
mr fantastic
Quote:

Originally Posted by Rhode963
So I've got to find the general solution of the following, and this is my work... did I do it right?

$(1+x)\frac{dy}{dx}=4y$

$(4+4x)\frac{dy}{dx}=y$ Mr F says: This is wrong. You should be dividing by 4. This mistake has consequences.

$\frac{dy}{y}=\frac{dx}{4+4x}$
$ln|y|=\frac{1}{4}ln|4x+4|$
$y=\frac{+}{-}x+1$

..
• October 1st 2010, 02:50 AM
elemental
Don't forget the integrating constant.