Hi I have some problem at the end...

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- Sep 24th 2010, 06:45 AMsf1903differential equation solution
Hi I have some problem at the end...

Attachment 19038(Shake)(Happy)http://www.mathhelpforum.com/math-he...isc/pencil.png - Sep 24th 2010, 07:04 AMKrizalid
the constant was found by the initial condition, once found you put in into the general solution of the ODE.

- Sep 29th 2010, 02:43 AMsf1903
If the initial condition is: y=(x^3)+C/x and C=2

how does x^3 become x^2?

The correct answer should be y=(x^2)+2/x

Thanks - Sep 29th 2010, 02:58 AMProve It
It must be a typo.

$\displaystyle y = x^3 + \frac{2}{x}$ is correct. - Sep 29th 2010, 03:04 AMsf1903
Awesome thanks!