# differential equation solution

• Sep 24th 2010, 06:45 AM
sf1903
differential equation solution
Hi I have some problem at the end...

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• Sep 24th 2010, 07:04 AM
Krizalid
the constant was found by the initial condition, once found you put in into the general solution of the ODE.
• Sep 29th 2010, 02:43 AM
sf1903
If the initial condition is: y=(x^3)+C/x and C=2
how does x^3 become x^2?

The correct answer should be y=(x^2)+2/x
Thanks
• Sep 29th 2010, 02:58 AM
Prove It
It must be a typo.

$y = x^3 + \frac{2}{x}$ is correct.
• Sep 29th 2010, 03:04 AM
sf1903
Awesome thanks!