1. ## DE help...

x^2 dy/dx = 1 - x^2 + y^2 - x^2y^2

I can't figure out how to break this up. Any advice? Thanks.

2. Nevermind, I got it!

3. Originally Posted by jzellt
x^2 dy/dx = 1 - x^2 + y^2 - x^2y^2

I can't figure out how to break this up. Any advice? Thanks.

$x^2 \frac{dy}{dx} = 1 - x^2 + y^2 - x^2y^2$

$\frac{dy}{dx} = \frac{1}{x^2} - 1 +\frac{ y^2}{x^2} -y^2$

$\frac{dy}{dx} = \frac{1}{x^2} - 1 +y^2\left(\frac{ 1}{x^2} -1\right)$

$\frac{dy}{dx} = \left(1-y^2\right)\left(\frac{ 1}{x^2} -1\right)$

Can you separate?