I'm having some trouble solving this differential equation Solve $\displaystyle \dfrac{dy}{dx}=(y-x)^2$ using the substitution $\displaystyle u=y-x$ Do I have to find $\displaystyle \dfrac{dy}{du}$?
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Why would you need that? $\displaystyle \dfrac{du}{dx}\;=\;\dfrac{dy}{dx} - 1$ is good enough, isn't it?
So would $\displaystyle \dfrac{du}{dx}=u^2-1$
Looks good so far.
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