I'm having some trouble solving this differential equation

Solve $\displaystyle \dfrac{dy}{dx}=(y-x)^2$ using the substitution $\displaystyle u=y-x$

Do I have to find $\displaystyle \dfrac{dy}{du}$?

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- Sep 2nd 2010, 07:51 PMacevipaDifferential equations special substitutions
I'm having some trouble solving this differential equation

Solve $\displaystyle \dfrac{dy}{dx}=(y-x)^2$ using the substitution $\displaystyle u=y-x$

Do I have to find $\displaystyle \dfrac{dy}{du}$? - Sep 2nd 2010, 08:09 PMTKHunny
Why would you need that? $\displaystyle \dfrac{du}{dx}\;=\;\dfrac{dy}{dx} - 1$ is good enough, isn't it?

- Sep 2nd 2010, 08:24 PMacevipa
So would $\displaystyle \dfrac{du}{dx}=u^2-1$

- Sep 3rd 2010, 02:18 AMAckbeet
Looks good so far.