Find the position function x(t) of a moving particle with the given acceleration a(t), intial position x0 = x(0), and initial velocity v0 = v(0).
a(t) = 1/sqRoot(t+4), v0 = -1, x0 = 1
Im at a loss. Any help is appreciated.
You are expected to know:
s(t) = x'(t)
a(t) = s'(t)
Given a(t), you must find the antiderivative and use the value provided to determine the coefficient. This gives v(t).
Given v(t), you must find the antiderivative and use the value provided to determine the coeficcient. This gives x(t).