Which method do I use to solve
(1 + t^2) dy/dt + 2ty = -picos(pi*t) y(0) = 0
I couldn't find a method to match this DE
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Well I don't if you can see it or not, but the LHS says this
ay'+a'y = ay (product rule)
since d/dt(1+t^2) = 2t and y->y'
we can say LHS = (1+t^2)*y = -pic0s(pi*t)
or you can simply use the p(x)=e^int(something)
I think you actually mean .
So that means .
Go from here.
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