dy/dx = x(y-1)
dy/(y-1) = xdx
Hi All, new to the forum!
Having a few problems with this question: "Use the separation of variables method to solve the first ordinary differential equation dy/dx = x(y-1) given that when x = -, y = 4
I came up with two answers... 12 and 1.099 and I'm not sure which one is correct, if any of them are correct! Any help will be deeply appreciated, thanks!
Thanks for the quick replies, I have 2 answers which I got not sure if there correct...
∫(y-1) dy = ∫x dx
y^2 /2 - y = x^2 /2 + C1
Multiplied both sides by 2
y^2 - y + x^2 = C
Do I need to find 'C' in order to answer this question?
My second answer is,
∫1/y-1 dy = ∫x dx
ln(y-1) = x^2 /2 + C1
Mutliplied both sides by 2
ln(y-1) + x^2 = C
Again do I need to find 'C' to answer this question or just leave it with at the integrated solution?
Sorry, but from what I can see your problem is mainly algebra not calculus. You would be well-advised to take much greater care with the algebra. And it wouldn't hurt to review your class notes and textbook on solving differential equations.