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Math Help - Integrate with respect to u

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    Integrate with respect to u

    Hello. Please can you help me integrate with respect to u:

    q_{uu} = (\frac{u-3}{2u})q_{u}
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Anne05 View Post
    Hello. Please can you help me integrate with respect to u:

    q_{uu} = (\frac{u-3}{2u})q_{u}
    Let \displaystyle y(u) = q_u

    Then you have

    \displaystyle y' = \left( \frac {u - 3}{2u} \right)y .......................where \displaystyle y' = \frac {dy}{du}

    \displaystyle \Rightarrow \frac {y'}y = \frac {u - 3}{2u}

    Solve this differential equation for \displaystyle y, and then you can solve for \displaystyle q

    See if you can finish up
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