# Integrate with respect to u

• Jul 2nd 2010, 09:53 AM
Anne05
Integrate with respect to u
Hello. Please can you help me integrate with respect to u:

$q_{uu} = (\frac{u-3}{2u})q_{u}$
• Jul 2nd 2010, 12:13 PM
Jhevon
Quote:

Originally Posted by Anne05
Hello. Please can you help me integrate with respect to u:

$q_{uu} = (\frac{u-3}{2u})q_{u}$

Let $\displaystyle y(u) = q_u$

Then you have

$\displaystyle y' = \left( \frac {u - 3}{2u} \right)y$ .......................where $\displaystyle y' = \frac {dy}{du}$

$\displaystyle \Rightarrow \frac {y'}y = \frac {u - 3}{2u}$

Solve this differential equation for $\displaystyle y$, and then you can solve for $\displaystyle q$

See if you can finish up