Hello. Please can you help me integrate with respect to u:

$\displaystyle q_{uu} = (\frac{u-3}{2u})q_{u}$

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- Jul 2nd 2010, 09:53 AMAnne05Integrate with respect to u
Hello. Please can you help me integrate with respect to u:

$\displaystyle q_{uu} = (\frac{u-3}{2u})q_{u}$ - Jul 2nd 2010, 12:13 PMJhevon
Let $\displaystyle \displaystyle y(u) = q_u$

Then you have

$\displaystyle \displaystyle y' = \left( \frac {u - 3}{2u} \right)y$ .......................where $\displaystyle \displaystyle y' = \frac {dy}{du}$

$\displaystyle \displaystyle \Rightarrow \frac {y'}y = \frac {u - 3}{2u}$

Solve this differential equation for $\displaystyle \displaystyle y$, and then you can solve for $\displaystyle \displaystyle q$

See if you can finish up