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Math Help - Need help getting started...

  1. #1
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    Question Need help getting started...

    Hey guys I hope you can help me out with these two.



    I think the first one is separable but I can't see how to isolate the variables. It's not exact nor can it be made exact by an integrating factor, at least I don't think it can be.

    The second one I need to get in terms of y/x (dy/dx = f(y/x)) to use the z substitution method. That root xy has got me stuck.

    Any help is much appreciated! Thanks!

    -Tony
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  2. #2
    Master Of Puppets
    pickslides's Avatar
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    Your link to the questions is not clear.

    Recall \sqrt{xy} =\sqrt{x}\sqrt{y}
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  3. #3
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    If you have [IMG] code on, it will be.

    But here is the direct link.
    http://i551.photobucket.com/albums/i...Untitled-6.png

    I got the second one now, thank you! I'm still unsure about the first one.

    -Tony
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  4. #4
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    Quote Originally Posted by Xplorer View Post
    Hey guys I hope you can help me out with these two.



    I think the first one is separable but I can't see how to isolate the variables. It's not exact nor can it be made exact by an integrating factor, at least I don't think it can be.

    The second one I need to get in terms of y/x (dy/dx = f(y/x)) to use the z substitution method. That root xy has got me stuck.

    Any help is much appreciated! Thanks!

    -Tony
    The right hand side of your first one can be written \frac{x (y + 3) - (y + 3)}{x (y - 2) + 4 (y - 2)}, it should now be clear how to continue.
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  5. #5
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    Quote Originally Posted by mr fantastic View Post
    The right hand side of your first one can be written \frac{x (y + 3) - (y + 3)}{x (y - 2) + 4 (y - 2)}, it should now be clear how to continue.
    Thats the ticket!

    Thank You!!

    -Tony
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