Results 1 to 2 of 2

Math Help - Exponential decay

  1. #1
    Newbie
    Joined
    Apr 2010
    Posts
    13

    Exponential decay

    have a problem with understanding how this integration took place:

    dx/dt = -kx

    x(t) = x0 exp(-kt)

    the lecture i attended just said by integration of the first equation we obtain x(t)
    and x0 is the initial avlue of x and exp is the exponential
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member
    Joined
    Dec 2009
    From
    1111
    Posts
    872
    Thanks
    3
    Quote Originally Posted by myenemy View Post
    have a problem with understanding how this integration took place:

    dx/dt = -kx

    x(t) = x0 exp(-kt)

    the lecture i attended just said by integration of the first equation we obtain x(t)
    and x0 is the initial avlue of x and exp is the exponential
    Dear myenemy,

    You have to use the seperation of variable method to solve this differential equation,

    \frac{dx}{dt}=-kx

    \frac{dx}{x}=-k~dt

    \int\frac{1}{x}dx=-\int{k~dt}

    Hope you can continue from here.
    Last edited by Sudharaka; June 18th 2010 at 09:52 PM.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Exponential Decay
    Posted in the Math Topics Forum
    Replies: 6
    Last Post: April 15th 2013, 01:19 AM
  2. exponential decay
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: July 23rd 2010, 12:03 AM
  3. Decay rates in exponential decay
    Posted in the Math Topics Forum
    Replies: 2
    Last Post: December 21st 2009, 07:20 AM
  4. Exponential Decay
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: October 11th 2008, 07:48 AM
  5. Exponential decay
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: March 31st 2008, 09:33 AM

Search Tags


/mathhelpforum @mathhelpforum