have a problem with understanding how this integration took place: dx/dt = -kx x(t) = x0 exp(-kt) the lecture i attended just said by integration of the first equation we obtain x(t) and x0 is the initial avlue of x and exp is the exponential
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Originally Posted by myenemy have a problem with understanding how this integration took place: dx/dt = -kx x(t) = x0 exp(-kt) the lecture i attended just said by integration of the first equation we obtain x(t) and x0 is the initial avlue of x and exp is the exponential Dear myenemy, You have to use the seperation of variable method to solve this differential equation, Hope you can continue from here.
Last edited by Sudharaka; Jun 18th 2010 at 09:52 PM.
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