Find the particular solution for the differential equation that satisfies the initial conditions , when .

Substituting , I got and , so the general solution is

What I don't know is how to make use of the initial conditions to find and .

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- June 9th 2010, 05:39 PMHibachiInitial conditions
Find the particular solution for the differential equation that satisfies the initial conditions , when .

Substituting , I got and , so the general solution is

What I don't know is how to make use of the initial conditions to find and . - June 9th 2010, 05:51 PMslider142
Find (dx/dt)(t):

Now you can get two equations in two unknowns using the two initial conditions: (dx/dt)(0) = 2 and x(0) = 0. - June 9th 2010, 06:11 PMHibachi