Here's an exercise from Tenebaum & Pollard's book:
I know how to show that the bottom one is the solution of the top equation, what I don't understand is why the interval on which the solution works is not:Differential equation:
Give the interval on which the solution makes sense.
as given the by author.
Trying to understand this intuitively, I'm thinking that anything multiplied by zero is zero. So when , anything substituted on the left hand side gives zero. However, if is the solution, when , the RHS is always zero.
I don't see where the restriction comes from.
Thanks for your help!