Find the unique function satisfying the differential equation with initial condition,

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- May 19th 2010, 07:59 PMExotiqueDifferential equation with initial conditions
Find the unique function satisfying the differential equation with initial condition,

, - May 19th 2010, 08:06 PM11rdc11
- May 19th 2010, 08:23 PMExotique
I'm guessing I have to solve for y in terms of x, let y = 1 and x = 1, then solve for C?

This is what I did:

Since ,

For some reason this doesn't feel right.

Then the original equation should be:

- May 19th 2010, 08:35 PM11rdc11
- May 19th 2010, 08:46 PMExotique
How did you get from

to

- May 19th 2010, 08:55 PMpickslides
to the power of an arbitrary constant remains an arbitrary constant. Therefore we can say

- May 19th 2010, 08:57 PMExotique
Ahh, I understand now, thank you to all.

- May 19th 2010, 08:59 PMmr fantastic