Results 1 to 2 of 2

Math Help - Euler Method - IVP

  1. #1
    Junior Member
    Joined
    Apr 2010
    Posts
    56

    Euler Method - IVP

    Just to clarify that I am on the right track, for the following problem:


    <br /> <br />
\frac{dy}{dx} = (x^2y-2e^x)<br />

    Will the formula using euler method look like:

    <br /> <br />
y_{n+1} = y_{n} + h({x_{n}}^2y_{n}-2e^{x_{n}})<br /> <br />

    , with h = 0.25

    I was just unsure if this is how you do it for exponentials.

    thanks in advance

    Follow Math Help Forum on Facebook and Google+

  2. #2
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    4
    Quote Originally Posted by olski1 View Post
    Just to clarify that I am on the right track, for the following problem:


    <br /> <br />
\frac{dy}{dx} = (x^2y-2e^x)<br />

    Will the formula using euler method look like:

    <br /> <br />
y_{n+1} = y_{n} + h({x_{n}}^2y_{n}-2e^{x_{n}})<br /> <br />

    , with h = 0.25



    That is correct
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Euler's Method
    Posted in the Differential Equations Forum
    Replies: 2
    Last Post: April 6th 2011, 03:27 PM
  2. Euler's method
    Posted in the Calculus Forum
    Replies: 0
    Last Post: March 8th 2010, 04:48 PM
  3. Euler's Method
    Posted in the Differential Equations Forum
    Replies: 2
    Last Post: November 9th 2009, 07:20 AM
  4. Euler Method
    Posted in the Math Software Forum
    Replies: 5
    Last Post: March 15th 2009, 02:58 PM
  5. Euler's Method
    Posted in the Differential Equations Forum
    Replies: 2
    Last Post: March 11th 2009, 05:33 PM

Search Tags


/mathhelpforum @mathhelpforum