Laplace of cosh (sorry urgent)

**Peleus** · May 11th 2010, 04:09 PM

Hi all,

Sorry I hate posting urgent questions up here but either way I need some help.

I'm looking for the laplace of $\cosh^2{t}$ but I've got no idea how to go about it, can anyone help out?

Cheers.

**dwsmith** · May 11th 2010, 04:29 PM

Originally Posted by Peleus

Hi all,

Sorry I hate posting urgent questions up here but either way I need some help.

I'm looking for the laplace of $\cosh^2{t}$ but I've got no idea how to go about it, can anyone help out?

Cheers.

$cosh=\frac{e^x+e^{-x}}{2}$

**chisigma** · May 11th 2010, 08:43 PM

Is...

$\cosh^{2} t = \frac{1}{2} + \frac{e^{2t} + e^{-2t}}{4}$ (1)

... so that...

$\mathcal{L} \{\cosh^{2} t\} = \frac{1}{2s} + \frac{1}{4(s-2)} + \frac{1}{4(s+2)}$ (2)

Kind regards

$\chi$ $\sigma$

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