Hi all,

Sorry I hate posting urgent questions up here but either way I need some help.

I'm looking for the laplace of $\displaystyle \cosh^2{t}$ but I've got no idea how to go about it, can anyone help out?

Cheers.

Printable View

- May 11th 2010, 04:09 PMPeleusLaplace of cosh (sorry urgent)
Hi all,

Sorry I hate posting urgent questions up here but either way I need some help.

I'm looking for the laplace of $\displaystyle \cosh^2{t}$ but I've got no idea how to go about it, can anyone help out?

Cheers. - May 11th 2010, 04:29 PMdwsmith
- May 11th 2010, 08:43 PMchisigma
Is...

$\displaystyle \cosh^{2} t = \frac{1}{2} + \frac{e^{2t} + e^{-2t}}{4}$ (1)

... so that...

$\displaystyle \mathcal{L} \{\cosh^{2} t\} = \frac{1}{2s} + \frac{1}{4(s-2)} + \frac{1}{4(s+2)}$ (2)

Kind regards

$\displaystyle \chi$ $\displaystyle \sigma$