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**MathsDude69** This is literally the first day ive ever encountered laplace transformation so I'm gonna apologise in advance if the answer to this question is blantantly obvious. I am currently trying to solve the following equation using laplace transformation:

$\displaystyle dy/dt + 3y = e^-5t$

Subject to the initial condition that y(0) = 1

The laplace transform I have as:

$\displaystyle [sX(s) - y(0)] + 3X(s) = 1/(s + 5)$

In all the previous examples I have thus far completed the initial condition has been y(0) = 0, and therefore the y(0) term in the laplace equation can be disregarded leaving:

$\displaystyle X(s) = 1/(s + 3)(s + 5)$

Which is in my laplace transform tables under:

$\displaystyle X(s) = k/(s + a)(s + B)$

Where k, a and B are constants

However if the intitial condition is y(0) = 1, the equation now becomes:

$\displaystyle X(s) = 1/(s + 3)(s + 5) + 1$

I now have the issue that the equation no longer fits my laplace table equation and I cannot locate an inverse laplace transform simply for a constant. Does anyone know how this equation can be rearranged back in terms of x(t)? Thanks