which has the characteristic equation
so the general solution is
but
so the final solution is
I am suppose to solve y'=5y; y(0)=1
However, I don't understand how to do this as the standard form for this type of equation seems to be: y' + a(t)y = b(t)
What do I use as b(t)?
Everything I've done so far works out to zero. Could someone explain?