Given that $\displaystyle g(t)$ has the Laplace transform of $\displaystyle G(s)$, what is the Laplace transform of H(s):

$\displaystyle h(t)=e^{-t}g'(3t)$

I know that $\displaystyle g(t)$ has to satisfy the Derivatives proptery theorem: $\displaystyle f'(t)=s F(s)-f(0)$, but im not really sure what to do. As always step by step instructions would be amazing