Originally Posted by

**iyppxstahh** I'm having some trouble with this assignment:

Suppose the rate at which the volume in a tank decreases is proportional to the square root of the volume present. The tank initially contains 25 gallons, but has 20.25 gallons after 3 minutes.

1. Write a differential equation that models this situation, Let V represent the volume (in gallongs) in the tank and t represent the time (in minutes).

- dV/dt=k*sqrtV

2. Solve for the general solution (do not solve for V).

-I WAS going to solve for V, but it says not to. So I thought maybe it's meaning to find the integral? Which is :

(2*k*v^(3/2)/3) = t