I am having trouble with this problem:

$\displaystyle x^2y'-4xy=x^7e^{x^2}+3x^5 $

First step I divided by $\displaystyle x^2 $ then I find that p(x)= -4/x and q(x)=$\displaystyle x^5e{x^2}+3x^2$. I that right? Well, if that is right, I am stuck at that point.