hello,
im having difficulty answering this question, please could somebody spare sometime answering it.. it starts off an exam paper and is putting me off the whole thing..

wats da general solution of

(∂^2/∂x∂t )f(x,t)=xt

2. Do you mean $\frac{\delta^2 f}{\delta x \delta t} = xt$? In which case, integrating once with respect to t,

$\frac{\delta f}{\delta x} = \frac{xt^2}{2} + A'(x)$ where A is arbitrary. Integrating again with respect to x we get

$f(x,t) = \frac{(xt)^2}{4} + A(x) + B(t)$ With B also being arbitrary.

3. ## A'(x)??

thank-you for ur reply.. not too sure why you have got A'(x) in the first part.. but then for the B arbitary constant you have B(t), shouldnt this be B'(t) too. I underdstand why A'(x) becomes A(x), or maybe i have not got the concept wright????