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Thread: Trigonometric Phase Lines

  1. #1
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    Trigonometric Phase Lines

    Hi,
    As part of a recent assignment I have been asked to draw a phase line for the function \frac{dy}{dt} = sin(y). I can find the main equilibrium point easily ( y = 0) but the problem I have is that y =  180,  y = 360,  y = 540 are also solutions. So in a way I have a phase line that continues infinitely. Is there any formal way of setting this out. The main idea that comes to mind is including an algebraic multiplier of both 180 and -180 on the phase line the stating a \in Z when a is the multiplier.

    Thoughts?
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  2. #2
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    Usually with trig functions, one will write k\pi. That way for any integer you will hit all multiples of \pi or 180
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  3. #3
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    thanks dwsmith I figured it would be something like that.
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