# Laplace Transform problem

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• Apr 8th 2010, 06:09 AM
steph3824
Laplace Transform problem
Use the Laplace transform to solve the initial value problem.
$y''-2y'+2y=cos t, y(0)=1, y'(0)=0$

Ok, so after doing the Laplace of both sides I am getting that $Y(s)=s-2+(s/s^2+1)/s^2-2s+2$

I am pretty sure that is correct but you may want to check me on that. Anyways, I am not sure what Y(s) becomes after this. Can someone help please?
• Apr 8th 2010, 07:15 AM
dwsmith
When you do the inverse LaPlace Transform of Y(s), you will have a y(t)