Try this function
f(t)=4tH(t)H(3-t)+12H(t-3)
I have a function f(t) = 4t if 0 <= t <= 3 and f(t) = 12 if t > 3.
My question is how to take the Heaviside of this, I'm not 100% comfortable with Heaviside in this case so I was wondering if someone could explain this. I know c = 3 but I'm not sure how to account for 12 and 4t properly.
Thanks