Hello,

given the equation: x= sin(t²)/2 + C I want to draw this in an interval [0,2]

My try:

Setting T to be 0,1 and 2; resulted in:

t = 0; results in: sin(0²)/2 + C = 0 + C

t = 1; results in: sin(1²)/2 + C = 0.008726 + C

t = 2; results in: sin(2²)/2 + C = 0.034878 + C

So, is T the X value and Y is the answer? Or is it vice versa? (Cannot believe I am asking, but better safe than sorry).

Thanks in advance.