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Math Help - Equi Potential Equations or Euler Type Equations

  1. #1
    Apr 2010

    Equi Potential Equations or Euler Type Equations

    Hello All

    I want to know about "Equi-Potential Equations" which are also known as "Euler Type Equations". I have less exposure to these equations. I also searched on net but didn't get a clear view of it. Can you explain or provide some references regarding these equations.

    Thanks in advance
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  2. #2
    MHF Contributor

    Apr 2005
    The main thing you need to know about "Euler-type" equations is that there is a "one-to-one" correspondence between them and equations with constant coefficients.

    Just as you can "look for" solutions to equations with constant coefficients using e^{rx} (even though solutions may not be exponential), so you can "look for" solutions to "Euler-type" equations using x^r.

    That's because the change of variable x= ln(t) will change an "Euler-type" equation in variable t to an equation with constant coefficients in variable t.

    For example, at^2 \frac{d^2y}{dt^2}+ bt\frac{dy}{dt}+ cy= 0 is an "Euler-type" equation in variable t. If we let x= ln(t), then \frac{dy}{dt}= \frac{dy}{dx}\frac{dx}{dt}= \frac{1}{t} \frac{dy}{dx}.

    Further \frac{d^2y}{dt^2}= \frac{d}{dt}\left(\frac{1}{t} \frac{dy}{dx}\right) = \frac{1}{t}\frac{d}{dt}\left(\frac{1}{t}\frac{dy}{  dx}\right)= \frac{1}{x}\left(\frac{1}{t}\frac{d^2y}{dx}^2- \frac{1}{t^2}\frac{dy}{dx}\right).

    So at^2\frac{d^2y}{dt^2}+ bt\frac{dy}{dt}+ cy = a\left(\frac{d^2y}{dx^2}- \frac{dy}{dx}\right)+ b\frac{dy}{dx}+ cy = a\frac{d^2y}{dx^2}+ (b- a)\frac{dy}{dx}+ cy= 0.
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