$\displaystyle y'/y^2 = x^2/y + 1;z=1/y;z'=-y'/y^2;$
$\displaystyle -z'=x^2z + 1;z=uv;z'=u'v + uv';$
$\displaystyle u'v + uv' + uvx^2 + 1=0;u(v' + vx^2)=0$
find v and further is easy
wish my DE were that easy too
$\displaystyle y'/y^2 = x^2/y + 1;z=1/y;z'=-y'/y^2;$
$\displaystyle -z'=x^2z + 1;z=uv;z'=u'v + uv';$
$\displaystyle u'v + uv' + uvx^2 + 1=0;u(v' + vx^2)=0$
find v and further is easy
wish my DE were that easy too