# whats wrong with my solution

• Mar 31st 2010, 11:58 PM
noteiler
whats wrong with my solution
the last integral does not integrate :

$xy' - y=ln(y); x=(ln(y) + y)/y'; y' = p; x=(ln(y) + y)/p;$

$dx=-1/p^2 (ln(y) + y)dp + (1/yp + 1/p)dy;$

$(ln(y)/p^2 + y/p^2)dp=dy/yp; dp/p = dy/(yln(y)+y^2)$
• Apr 1st 2010, 02:45 AM
mr fantastic
Quote:

Originally Posted by noteiler
the last integral does not integrate :

$xy' - y=ln(y); x=(ln(y) + y)/y'; y' = p; x=(ln(y) + y)/p;$

$dx=-1/p^2 (ln(y) + y)dp + (1/yp + 1/p)dy;$

$(ln(y)/p^2 + y/p^2)dp=dy/yp; dp/p = dy/(yln(y)+y^2)$

The solution involves an integral that cannot be found using a finite number of elementary functions: integrate 1&#x2f;&#x28;Log&#x5b;y&#x5d; &#x2b; y&#x29; - Wolfram|Alpha

Where has the DE come from?
• Apr 1st 2010, 05:44 AM
noteiler
this DE was given to me by university tutor. and yes, i know that function doesn't integrate in elementary functions, but i thought that i am doing something wrong. by the way i have plenty DEs that i can't solve duo to integration for example in attachment. i think that i'm just doing something wrong. can someone help me.