Results 1 to 2 of 2

- March 27th 2010, 04:32 PM #1

- Joined
- Jan 2010
- Posts
- 133

## xy'= yln(xy)

Hello everyone,

i got this ODE - xy' = yln(xy)

So i did a simple substitution of u for xy, so u' = y + xy'

u' - y = ylnu equivelent to saying u' / 1 + ln u = y

so integrating the RHS would be simple, but i dont know with what i should integrate y, well if i work it out with the differential operators, i guess i must integrate y with dx, but how...

Any help would be very much appreciated.

- March 27th 2010, 04:34 PM #2