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- Mar 27th 2010, 03:32 PM #1

- Joined
- Jan 2010
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- 133

## xy'= yln(xy)

Hello everyone,

i got this ODE - xy' = yln(xy)

So i did a simple substitution of u for xy, so u' = y + xy'

u' - y = ylnu equivelent to saying u' / 1 + ln u = y

so integrating the RHS would be simple, but i dont know with what i should integrate y, well if i work it out with the differential operators, i guess i must integrate y with dx, but how...

Any help would be very much appreciated.

- Mar 27th 2010, 03:34 PM #2

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