Originally Posted by
TheFirstOrder cy''+(2-c)y'-y=e^t
I'm not sure how to approach this equation. I've already found the particular solution for this, which is Y(t)=e^t.
I tried to find the complementary solution for it by using the quadratic equation and trying to find the required numbers that way, but I've been told that that method doesn't work. But here's the work i've done so far:
Work: tu^2+(2-t)u-1=0
tu^2-tu+2u-1=0
when t=/0, u=+-(an ugly imaginary no.)
when t=0, 2u-1=0
u=1/2
thus, com. function is y=c1e^1/2t+c2e^1/2t
I've been told that this is wrong. I'm still really confused as to what to do...