1. ## Separable Differential Equation

I am confunsed with this problem:

$\displaystyle dy/dx=y + 1/y^2$

would it be:
$\displaystyle \int y^2(y-dy) = \int dt$ ?

2. Originally Posted by littlesohi
I am confunsed with this problem:

$\displaystyle dy/dx=y + 1/y^2$

would it be:
$\displaystyle \int y^2(y-dy) = \int dt$ ?
I do not know what the hell is dt ?!

It will be:
$\displaystyle \frac{dy}{y+\frac{1}{y^2}}=dx$ ..

NOTE: There is a sub-forum for the differential equations ..

3. Yeah i'm sorry it should be dx. But the derivative of the left side would be what you said? I know that the right side would be just x, but I don't know how to resolved for the left side.

4. Originally Posted by littlesohi
But the derivative of the left side would be what you said?
I did not say anything about the derivatives ..

5. I mean the integral, sorry I'm working on other problems also and I'm gnow a mess. Can you help me with the left side please?

6. Originally Posted by littlesohi
I mean the integral, sorry I'm working on other problems also and I'm gnow a mess. Can you help me with the left side please?
Multiply the integrand by $\displaystyle \, \frac{y^2}{y^2}$ to get :
$\displaystyle \int \frac{y^2}{y^3+1} \, dy$ .. which is easy ..