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Thread: Separable Differential Equation

  1. March 25th 2010, 12:54 PM #1
    littlesohi
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    Separable Differential Equation

    I am confunsed with this problem:

    dy/dx=y + 1/y^2

    would it be:
    \int y^2(y-dy) = \int dt ?
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  2. March 25th 2010, 12:56 PM #2
    General
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    Quote Originally Posted by littlesohi View Post
    I am confunsed with this problem:

    dy/dx=y + 1/y^2

    would it be:
    \int y^2(y-dy) = \int dt ?
    I do not know what the hell is dt ?!

    It will be:
    \frac{dy}{y+\frac{1}{y^2}}=dx ..

    NOTE: There is a sub-forum for the differential equations ..
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  3. March 25th 2010, 01:25 PM #3
    littlesohi
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    Yeah i'm sorry it should be dx. But the derivative of the left side would be what you said? I know that the right side would be just x, but I don't know how to resolved for the left side.
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  4. March 25th 2010, 01:26 PM #4
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    Quote Originally Posted by littlesohi View Post
    But the derivative of the left side would be what you said?
    I did not say anything about the derivatives ..
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  5. March 25th 2010, 02:39 PM #5
    littlesohi
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    I mean the integral, sorry I'm working on other problems also and I'm gnow a mess. Can you help me with the left side please?
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  6. March 25th 2010, 03:17 PM #6
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    Quote Originally Posted by littlesohi View Post
    I mean the integral, sorry I'm working on other problems also and I'm gnow a mess. Can you help me with the left side please?
    Multiply the integrand by \, \frac{y^2}{y^2} to get :
    \int \frac{y^2}{y^3+1} \, dy .. which is easy ..
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