I am confunsed with this problem: $\displaystyle dy/dx=y + 1/y^2 $ would it be: $\displaystyle \int y^2(y-dy) = \int dt $ ?
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Originally Posted by littlesohi I am confunsed with this problem: $\displaystyle dy/dx=y + 1/y^2 $ would it be: $\displaystyle \int y^2(y-dy) = \int dt $ ? I do not know what the hell is dt ?! It will be: $\displaystyle \frac{dy}{y+\frac{1}{y^2}}=dx$ .. NOTE: There is a sub-forum for the differential equations ..
Yeah i'm sorry it should be dx. But the derivative of the left side would be what you said? I know that the right side would be just x, but I don't know how to resolved for the left side.
Originally Posted by littlesohi But the derivative of the left side would be what you said? I did not say anything about the derivatives ..
I mean the integral, sorry I'm working on other problems also and I'm gnow a mess. Can you help me with the left side please?
Originally Posted by littlesohi I mean the integral, sorry I'm working on other problems also and I'm gnow a mess. Can you help me with the left side please? Multiply the integrand by $\displaystyle \, \frac{y^2}{y^2}$ to get : $\displaystyle \int \frac{y^2}{y^3+1} \, dy $ .. which is easy ..
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