# Separable Differential Equation

• Mar 25th 2010, 01:54 PM
littlesohi
Separable Differential Equation
I am confunsed with this problem:

$dy/dx=y + 1/y^2$

would it be:
$\int y^2(y-dy) = \int dt$ ?
• Mar 25th 2010, 01:56 PM
General
Quote:

Originally Posted by littlesohi
I am confunsed with this problem:

$dy/dx=y + 1/y^2$

would it be:
$\int y^2(y-dy) = \int dt$ ?

I do not know what the hell is dt ?!

It will be:
$\frac{dy}{y+\frac{1}{y^2}}=dx$ ..

NOTE: There is a sub-forum for the differential equations ..
• Mar 25th 2010, 02:25 PM
littlesohi
Yeah i'm sorry it should be dx. But the derivative of the left side would be what you said? I know that the right side would be just x, but I don't know how to resolved for the left side.
• Mar 25th 2010, 02:26 PM
General
Quote:

Originally Posted by littlesohi
But the derivative of the left side would be what you said?

I did not say anything about the derivatives ..
• Mar 25th 2010, 03:39 PM
littlesohi
I mean the integral, sorry I'm working on other problems also and I'm gnow a mess. Can you help me with the left side please?
• Mar 25th 2010, 04:17 PM
General
Quote:

Originally Posted by littlesohi
I mean the integral, sorry I'm working on other problems also and I'm gnow a mess. Can you help me with the left side please?

Multiply the integrand by $\, \frac{y^2}{y^2}$ to get :
$\int \frac{y^2}{y^3+1} \, dy$ .. which is easy ..