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Math Help - Separable Differential Equations

  1. #1
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    Separable Differential Equations

    I need help in this problem!

    dy/dx=3x^2 (y-2)^2

    I moved the dx to the other side and divided by (y-2)^2 but I got stuck in that part. I know that I have to integrate but I don't know how to continue:

    \int dy/(y-2)^2 = \int 3x^2dx
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  2. #2
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    Quote Originally Posted by littlesohi View Post
    I need help in this problem!

    dy/dx=3x^2 (y-2)^2

    I moved the dx to the other side and divided by (y-2)^2 but I got stuck in that part. I know that I have to integrate but I don't know how to continue:

    \int dy/(y-2)^2 = \int 3x^2dx
    To integrate the left side, use the partial fractions method or substitute u=y-2 ..
    the right side should be easy ..
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  3. #3
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    So the left side would be -1/u?
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  4. #4
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    Quote Originally Posted by littlesohi View Post
    So the left side would be -1/u?
    Yes .. which is \frac{-1}{y-2} ..
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