I need help in this problem!

$\displaystyle dy/dx=3x^2 (y-2)^2$

I moved the dx to the other side and divided by (y-2)^2 but I got stuck in that part. I know that I have to integrate but I don't know how to continue:

$\displaystyle \int dy/(y-2)^2 = \int 3x^2dx $