Results 1 to 2 of 2

Math Help - Differential Equation Problem

  1. #1
    Newbie
    Joined
    Mar 2010
    Posts
    3

    Differential Equation Problem

    The question is broken down into two parts: a) find y in terms of x if with the initial conditions of y(0)=8 and b) for what x-interval is the solution defined?

    dx/dy=(x^4)/(y^7)

    For a) I have found it to be:

    ((8/5)x^5+8^8)^(1/8), which is correct.

    But for b) its stated as a number _______<x< infinity (which i found). So what I need help with, is how do I determine the number for the first part of the interval.

    Thanks.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Flow Master
    mr fantastic's Avatar
    Joined
    Dec 2007
    From
    Zeitgeist
    Posts
    16,948
    Thanks
    5
    Quote Originally Posted by Jewgro View Post
    The question is broken down into two parts: a) find y in terms of x if with the initial conditions of y(0)=8 and b) for what x-interval is the solution defined?

    dx/dy=(x^4)/(y^7)

    For a) I have found it to be:

    ((8/5)x^5+8^8)^(1/8), which is correct.

    But for b) its stated as a number _______<x< infinity (which i found). So what I need help with, is how do I determine the number for the first part of the interval.

    Thanks.
    Presumably \frac{8}{5} x^5 +8^8 \geq 0 ....
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 1
    Last Post: April 11th 2011, 02:17 AM
  2. differential equation problem
    Posted in the Differential Equations Forum
    Replies: 1
    Last Post: January 12th 2011, 03:02 PM
  3. Differential Equation Problem 2
    Posted in the Differential Equations Forum
    Replies: 2
    Last Post: September 28th 2009, 01:31 AM
  4. differential equation problem
    Posted in the Differential Equations Forum
    Replies: 2
    Last Post: May 29th 2009, 07:50 AM
  5. Problem with differential equation
    Posted in the Differential Equations Forum
    Replies: 6
    Last Post: February 22nd 2009, 04:58 PM

Search Tags


/mathhelpforum @mathhelpforum