# Differential Equation Problem

• Mar 25th 2010, 06:18 AM
Jewgro
Differential Equation Problem
The question is broken down into two parts: a) find y in terms of x if with the initial conditions of y(0)=8 and b) for what x-interval is the solution defined?

dx/dy=(x^4)/(y^7)

For a) I have found it to be:

((8/5)x^5+8^8)^(1/8), which is correct.

But for b) its stated as a number _______<x< infinity (which i found). So what I need help with, is how do I determine the number for the first part of the interval.

Thanks.
• Mar 26th 2010, 03:49 PM
mr fantastic
Quote:

Originally Posted by Jewgro
The question is broken down into two parts: a) find y in terms of x if with the initial conditions of y(0)=8 and b) for what x-interval is the solution defined?

dx/dy=(x^4)/(y^7)

For a) I have found it to be:

((8/5)x^5+8^8)^(1/8), which is correct.

But for b) its stated as a number _______<x< infinity (which i found). So what I need help with, is how do I determine the number for the first part of the interval.

Thanks.

Presumably $\frac{8}{5} x^5 +8^8 \geq 0$ ....