hey there..

i've got unsolved question here..

Question:

Solve the initial value problem.

2yy = x / √x^2 16 ; y(5) = 2

2yy = x / √x^2 16

2y dy/dx = x / √x^2 16

∫2y dy = ∫ x / √x^2 16 dx

y^2 + C = √x^2 16 + C

y = (√x^2 16)^1/2

my answer was wrong. the answer is y = ((√x^2 16) + 1)^1/2

how am i going to get the correct answer..?

and.. what is the use of y(5) = 2?