Thread: Serparable Differential Equation Question

Question:
Find if satisfies

and the -intercept of the curve is .
?

My work:
dy/dx = 12yx^3, y(0) = 6
integral 1/(12y) dy = integral x^3 dx
1/12 * ln|y| = e^(1/4 * x^4) + C
y^(1/12) = e^(1/4 * x^4) + C
y = e^(3x^4) + C
6 = e^0 + C
C = 5
y = e^(3x^4) + 5

What am I doing wrong?

Any help would be greatly appreciated!
Thanks in advance!

=



\



6 = C

you did what I did but C = 5 not 6 becase 6 - e^0 = C --> C = 6 - 1 = 5