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Math Help - Integration Confusion

  1. #1
    Junior Member
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    Integration Confusion

    I do not understand what method I can use to workout the following equation:

    <br />
\int\frac{1}{e^{4x + 1}} dx<br />

    My first instinct was to say that   \frac{1}{4} ln e^{4x + 1} <br />

    However it is my understanding that ln e would cancel each other out. Thus the original equation would have only been 4x + 1, and the derivative of that is merely 4. So, I seem to be doing something wrong, what am I missing?
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  2. #2
    Super Member Random Variable's Avatar
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     \int \frac{1}{e^{4x+1}} \ dx =  \int e^{-(4x+1)} \ dx

    Now let  u = -(4x+1)
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