1. I take it now all i need to do is
$50\ \theta\ e^{t/10}\ =\ 50e^{t/10} - 25te^{t/10} - (-250e^{t/10}) - 240$
$\theta\ = (\ 50e^{t/10} - 25te^{t/10} - (-250e^{t/10}) - 240) / (50 e^{t/10})$
So then i sub t=2 in to give me theta when t=2 seconds?

$\theta\ = (\ 50e^{2/10} - (25*2)e^{2/10} - (-250e^{2/10}) - 240) / (50 e^{2/10})$
is that correct?

2. Originally Posted by jamm89
is that correct?
You have at least two ways of checking. Differentiate the 'whole equation' to see if you can arrive at the original given equation. Also, is the answer realistic? Helps if you know was it heating or cooling? Maybe you don't know.

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