I take it now all i need to do is

$\displaystyle 50\ \theta\ e^{t/10}\ =\ 50e^{t/10} - 25te^{t/10} - (-250e^{t/10}) - 240$

$\displaystyle \theta\ = (\ 50e^{t/10} - 25te^{t/10} - (-250e^{t/10}) - 240) / (50 e^{t/10})$

So then i sub t=2 in to give me theta when t=2 seconds?

$\displaystyle \theta\ = (\ 50e^{2/10} - (25*2)e^{2/10} - (-250e^{2/10}) - 240) / (50 e^{2/10})$

is that correct?