find the second solution that is linearly independent to the solution given for
(1-x cot x)y'' - xy' +y = 0
y1(x) = x
hint : integration of (x/(1-x cot x)) dx = ln |x cos x - sin x|
i've tried to rearrage the equation in the form :
but how can i get y2(x) = function of x????
i get stack here... pls help me.....