Second Order differential equation problem

**Fwahm** · March 7th 2010, 07:51 PM

y''+9y=30sin(3x)

I'm told to use the method of solving y''+9y=30e^(3ix), but I'm not sure what to do after I find (D-3)(D-3)y=30e^(3ix).

Could I have some help?

**chisigma** · March 7th 2010, 11:21 PM

In terms of Laplace Transform the particular integral of...

$y^{''} + 9\cdot y = 30 \cdot \sin 3x$ (1)

... is written as...

$Y_{p} (s) = \frac{10}{(s^{2}+9)^{2}}$ (2)

... so that is...

$y_{p} (x) = \mathcal {L} \{Y_{p} (s)\} = \frac {5}{27}\cdot (\sin 3x - 3x\cdot \cos 3x)$ (3)

Alternatively [and is is a not confortable job

...] You can search for function of the type...

$y_{p} (x) = x \cdot (\alpha\cdot \cos 3x + \beta\cdot \sin 3x)$ (4)

... that satisfies (1)...

Kind regards

$\chi$ $\sigma$

Thread: Second Order differential equation problem

LinkBack

Thread Tools

Display

Second Order differential equation problem

Similar Math Help Forum Discussions

frist order differential equation problem

2nd order differential equation problem

First-order differential/seperable equation problem

Problem with first order separabel differential equation

First order differential equation problem

Search Tags