For any of the constant value k, the function y is a solution of the last equation. Find p and q. I've tried subbing in y and y' but I need P and Q explicitly. Don't know what to do.
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Originally Posted by DCU For any of the constant value k, the function y is a solution of the last equation. Find p and q. I've tried subbing in y and y' but I need P and Q explicitly. Don't know what to do. The key is the hint they gave you. It is true for every value of k So you get $\displaystyle \cos(x)-\frac{k}{x^2}+P(x)\left(\sin(x)+\frac{k}{x} \right)=Q(x)$ This is true for every value of k so pick some easy ones like $\displaystyle k=0,k=1$ and solve for P and Q.
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