The question is find the differential of each function: a) y=(t+tant)^5 and b) y=√(z+1/z)

Please Help Me. I only got the first steps:

a) dy/dt = 5(t+tan t)(1 +sec^2 x)

b) dy/dz= 0.5*(1/(z + 1/z)) * (1 - 1/z^2)

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- March 2nd 2010, 12:14 AMwatchthesky30find the differential of each function
The question is find the differential of each function: a) y=(t+tant)^5 and b) y=√(z+1/z)

Please Help Me. I only got the first steps:

a) dy/dt = 5(t+tan t)(1 +sec^2 x)

b) dy/dz= 0.5*(1/(z + 1/z)) * (1 - 1/z^2) - March 2nd 2010, 01:48 AMProve It