i) $\displaystyle dy/dx = (x-4y)/(4x+y)$
ii) $\displaystyle dy/dx = (x^2 + 2y^2)/xy$
I'm honestly not sure of the method. Google didn't give me much help either
Thanks in advance to anyone who can help.
i) $\displaystyle dy/dx = (x-4y)/(4x+y)$
ii) $\displaystyle dy/dx = (x^2 + 2y^2)/xy$
I'm honestly not sure of the method. Google didn't give me much help either
Thanks in advance to anyone who can help.