If has period T, then its Laplace transform is...
(1)
In Your case is and the integral in (1) is...
(2)
... that is easy to solve...
Kind regards
I'm having trouble setting up my equation.
Square wave with period T = 2a.
f(t) = 2, 0<t<a
f(t) = 0, a<t<2a
Take the Laplace Transform of f(t).
What I got:
F(s) = (∫2exp(-st)dt [0,a]) / [1 - exp(-2as)]
The square brackets [0,a] are the limits of the definite integral.
Thanks guys.