# Thread: Laplace Transform of Period Square Wave Function

1. ## Laplace Transform of Period Square Wave Function

I'm having trouble setting up my equation.

Square wave with period T = 2a.
f(t) = 2, 0<t<a
f(t) = 0, a<t<2a

Take the Laplace Transform of f(t).

What I got:

F(s) = (∫2exp(-st)dt [0,a]) / [1 - exp(-2as)]

The square brackets [0,a] are the limits of the definite integral.

Thanks guys.

2. If $\displaystyle f(t)$ has period T, then its Laplace transform is...

$\displaystyle F(s)= \mathcal{L} \{f(t)\}= \frac{\int_{0}^{T} e^{-st}\cdot f(t)\cdot dt}{1-e^{-sT}}$ (1)

In Your case is $\displaystyle T=2a$ and the integral in (1) is...

$\displaystyle \int_{0}^{a} 2\cdot e^{-st}\cdot dt$ (2)

... that is easy to solve...

Kind regards

$\displaystyle \chi$ $\displaystyle \sigma$

3. Perfect, thank you very much, good to know I was on the right track!

,

,

,

,

,

,

,

,

,

,

,

,

,

,

# single square wave in laplace transform

Click on a term to search for related topics.